The Great Pyramid of Cheops at El Gizeh, Egypt, had height H = 147 m before its topmost stone fell. Its base is a square with edge length L = 230 m. Its volume V is equal to L^2*H/3. Assuming that it has uniform density = 1.50脳10^3 kg/m^3, find the original height of its center of mass above the base.
Part 2
Find the work required to lift the blocks into place from the base level.|||1)H/4. Simply.
2)This requires you to find the mass by using the density formula (D = m/v). Solve for m. Then use mgh. With h being your center of mass from part 1.That's it. My answer was to the 12th power so don't worry if your answer is big.
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