The Great Pyramid of Cheops at El Gizeh, Egypt, had height H = 147 m before its topmost stone fell. Its base is a square with edge length L = 230 m. Its volume V is equal to L2H/3. Assuming that it has uniform density = 2.20脳103 kg/m3, find the original height of its center of mass above the base.|||H/4. Simply.
If you also have the second part to find the work then it
requires you to find the mass by using the density formula (D = m/v). Solve for m. Then use mgh. With h being your center of mass from part 1.That's it. My answer was to the 12th power so don't worry if your answer is big.
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